4800-120x-160x+4x^2=0

Solution for 4800-120x-160x+4x^2=0 equation:

4800-120x-160x+4x^2=0

We add all the numbers together, and all the variables

4x^2-280x+4800=0

a = 4; b = -280; c = +4800;
Δ = b2-4ac
Δ = -2802-4·4·4800
Δ = 1600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1600}=40$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-280)-40}{2*4}=\frac{240}{8}
=30
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-280)+40}{2*4}=\frac{320}{8}
=40
$